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Do 10x developers exist? I believe that they do, but not like you may think.

The notion that some software developers are ten times (10x) as productive as 'normal' developers is decades old. Once in a while, the discussion resurfaces. It's a controversial subject, but something I've been thinking about for years, so I thought that I'd share my perspective because I don't see anyone else arguing from this position.

While I'll try to explain my reasoning, I'll make no attempt at passing this off as anything but my current, subjective viewpoint. Please leave a comment if you have something to add.

Perspective #

Meet Yohan. You've probably had a colleague like him. He's one of those software developers who gets things done, who never says no when the business asks him to help them out, who always respond with a smile to any request.

I've had a few colleagues like Yohan in my career. It can be enlightening overhearing non-technical stakeholders discuss software developers:

Alice: Yohan is such a dear; he helped me out with that feature on the web site, you know...

Bob: Yes, he's a real go-getter. All the other programmers just say no and look pissed when I approach them about anything.

Alice: Yohan always says yes, and he gets things done. He's a real 10x developer.

Bob: We're so lucky we have him...

Overhearing such a conversation can be frustrating. Yohan is your colleague, and you've just about had enough of him. Yohan is one of those developers who'll surround all code with a try-catch block, because then there'll be no exceptions in production. Yohan will make changes directly to the production system and tell no-one. Yohan will copy and paste code. Yohan will put business logic in database triggers, or rewrite logs, or use email as a messaging system, or call, parse, and run HTML-embedded JavaScript code on back-end servers. All 'because it's faster and provides more business value.'

Yohan is a 10x developer.

You, and the rest of your team, get nothing done.

You get nothing done because you waste all your time cleaning up the trail of garbage and technical debt Yohan leaves in his wake.

Business stakeholders may view Yohan as being orders of magnitude more productive than other developers, because most programming work is invisible and intangible. Whether or not someone is a 10x developer is highly subjective, and depends on perspective.

Context #

The notion that some people are orders of magnitude more productive than the 'baseline' programmer has other problems. It implicitly assumes that a 'baseline' programmer exists in the first place. Modern software development, however, is specialised.

As an example, I've been doing test-driven, ASP.NET-based C# server-side enterprise development for decades. Drop me into a project with my favourite stack and watch me go. On the other hand, try asking me to develop a game for the Sony PlayStation, and watch me stall.

Clearly, then, I'm a 10x developer, for the tautological reason that I'm much better at the things that I'm good at than the things I'm not good at.

Even the greatest R developer is unlikely to be of much help on your next COBOL project.

As always, context matters. You can be a great programmer in a particular context, and suck in another.

This isn't limited to technology stacks. Some people prefer co-location, while others work best by themselves. Some people are detail-oriented, while others like to look at the big picture. Some people do their best work early in the morning, and others late at night.

And some teams of 'mediocre' programmers outperform all-star teams. (This, incidentally, is a phenomenon also sometimes seen in professional Soccer.)

Evidence #

Unfortunately, as I explain in my Humane Code video, I believe that you can't measure software development productivity. Thus, the notion of a 10x developer is subjective.

The original idea, however, is decades old, and seems, at first glance, to originate in a 'study'. If you're curious about its origins, I can't recommend The Leprechauns of Software Engineering enough. In that book, Laurent Bossavit explains just how insubstantial the evidence is.

If the evidence is so weak, then why does the idea that 10x developers exist keep coming back?

0x developers #

I think that the reason that the belief is recurring is that (subjectively) it seems so evident. Barring confirmation bias, I'm sure everyone has encountered a team member that never seemed to get anything done.

I know that I've certainly had that experience from time to time.

The first job I had, I hated. I just couldn't muster any enthusiasm for the work, and I'd postpone and drag out as long as possible even the simplest task. That wasn't very mature, but I was 25 and it was my first job, and I didn't know how to handle the situation I found myself in. I'm sure that my colleagues back then found that I didn't pull my part. I didn't, and I'm not proud of it, but it's true.

I believe now that I was in the wrong context. It wasn't that I was incapable of doing the job, but at that time in my career, I absolutely loathed it, and for that reason, I wasn't productive.

Another time, I had a colleague who seemed incapable of producing anything that helped us achieve our goals. I was concerned that I'd flipped the bozo bit on that colleague, so I started to collect evidence. Our Git repository had few commits from that colleague, and the few that I could find I knew had been made in collaboration with another team member. We shared an office, and I had a pretty good idea about who worked together with whom when.

This colleague spent a lot of time talking to other people. Us, other stakeholders, or any hapless victim who didn't escape in time. Based on these meetings and discussions, we'd hear about all sorts of ideas for improvements for our code or development process, but nothing would be implemented, and rarely did it have any relevance to what we were trying to accomplish.

I've met programmers who get nothing done more than once. Sometimes, like the above story, they're boisterous bluffs, but most often, they just sit quietly in their corner and fidget with who knows what.

Based on the above, mind you, I'm not saying that these people are necessarily incompetent (although I suspect that some are). They might also just find themselves in a wrong context, like I did in my first job.

It seems clear to me, then, that there's such a thing as a 0x developer. This is a developer who gets zero times (0x) as much done as the 'average' developer.

For that reason it seems evident to me that 10x developers exist. Any developer who regularly manages to get code deployed to production is not only ten times, but infinitely more productive than 0x developers.

It gets worse, though.

−nx developers #

Not only is it my experience that 0x developers exist, I also believe that I've met more than one −nx developer. These are developers who are minus n times 'more' productive than the 'baseline' developer. In other words, they are software developers who have negative productivity.

I've never met anyone who I suspected of deliberately sabotaging our efforts; they always seem well-meaning, but some people can produce more mess than three colleagues can clean up. Yohan, above, is such an archetype.

One colleague I had, long ago, was so bad that the rest of the team deliberately compartmentalised him/her. We'd ask him/her to work on an isolated piece of the system, knowing that (s)he would be assigned to another project after four months. We then secretly planned to throw away the code once (s)he was gone, and rewrite it. I don't know if that was the right decision, but since we had padded all other estimates accordingly, we made our deadlines without more than the usual overruns.

If you accept the assertion that −nx developers exist, then clearly, anyone who gets anything done at all is an ∞x developer.

Summary #

10x developers exist, but not in the way that people normally interpret the term.

10x developers exist because there's great variability in (perceived) productivity. Much of the variability is context-dependent, so it's less clear if some people are just 'better at programming' than others. Still, when we consider that people like Linus Torvalds exist, it seems compelling that this might be the case.

Most of the variability, however, I think correlates with environment. Are you working in a technology stack with which you're comfortable? Do you like what you're doing? Do you like your colleagues? Do you like your hours? Do you like your working environment?

Still, even if we could control for all of those variables, we might still find that some people get stuff done, and some people don't. The people who get anything done are ∞x developers.

Employers and non-technical start-up founders sometimes look for the 10x unicorns, just like they look for rock star developers.

"To really confuse recruiters, someone should make a programming language called Rockstar."

Perhaps we should also create a 10x programming language, so that we could put certified Rockstar programmer, 10x developer on our resumes.

Comments

One way to unit test a wai application with the API provided by Network.Wai.Test.

I'm currently developing a REST API in Haskell using Servant, and I'd like to test the HTTP API as well as the functions that I use to compose it. The Servant documentation, as well as the servant Stack template, uses hspec to drive the tests.

I tried to develop my code with hspec, but I found it confusing and inflexible. It's possible that I only found it inflexible because I didn't understand it well enough, but I don't think you can argue with my experience of finding it confusing.

I prefer a combination of HUnit and QuickCheck. It turns out that it's possible to test a wai application (including Servant) using only those test libraries.

Testable HTTP requests #

When testing against the HTTP API itself, you want something that can simulate the HTTP traffic. That capability is provided by Network.Wai.Test. At first, however, it wasn't entirely clear to me how that library works, but I could see that the Servant-recommended Test.Hspec.Wai is just a thin wrapper over Network.Wai.Test (notice how open source makes such research much easier).

It turns out that Network.Wai.Test enables you to run your tests in a Session monad. You can, for example, define a simple HTTP GET request like this:

import qualified Data.ByteString as BS
import qualified Data.ByteString.Lazy as LBS
import Network.HTTP.Types
import Network.Wai
import Network.Wai.Test

get :: BS.ByteString -> Session SResponse
get url = request $ setPath defaultRequest { requestMethod = methodGet } url

This get function takes a url and returns a Session SResponse. It uses the defaultRequest, so it doesn't set any specific HTTP headers.

For HTTP POST requests, I needed a function that'd POST a JSON document to a particular URL. For that purpose, I had to do a little more work:

postJSON :: BS.ByteString -> LBS.ByteString -> Session SResponse
postJSON url json = srequest $ SRequest req json
  where
    req = setPath defaultRequest
            { requestMethod = methodPost
            , requestHeaders = [(hContentType, "application/json")]} url

This is a little more involved than the get function, because it also has to supply the Content-Type HTTP header. If you don't supply that header with the application/json value, your API is going to reject the request when you attempt to post a string with a JSON object.

Apart from that, it works the same way as the get function.

Running a test session #

The get and postJSON functions both return Session values, so a test must run in the Session monad. This is easily done with Haskell's do notation; you'll see an example of that later in the article.

First, however, you'll need a way to run a Session. Network.Wai.Test provides a function for that, called runSession. Besides a Session a value, though, it also requires an Application value.

In my test library, I already have an Application, although it's running in IO (for reasons that'll take another article to explain):

app :: IO Application

With this value, you can easily convert any Session a to IO a:

runSessionWithApp :: Session a -> IO a
runSessionWithApp s = app >>= runSession s

The next step is to figure out how to turn an IO a into a test.

Running a property #

You can turn an IO a into a Property with either ioProperty or idempotentIOProperty. I admit that the documentation doesn't make the distinction between the two entirely clear, but ioProperty sounds like the safer choice, so that's what I went for here.

With ioProperty you now have a Property that you can turn into a Test using testProperty from Test.Framework.Providers.QuickCheck2:

appProperty :: (Functor f, Testable prop, Testable (f Property))
            => TestName -> f (Session prop) -> Test
appProperty name =
  testProperty name . fmap (ioProperty . runSessionWithApp)

The type of this function seems more cryptic than strictly necessary. What's that Functor f doing there?

The way I've written the tests, each property receives input from QuickCheck in the form of function arguments. I could have given the appProperty function a more restricted type, to make it clearer what's going on:

appProperty :: (Arbitrary a, Show a, Testable prop)
            => TestName -> (a -> Session prop) -> Test
appProperty name =
  testProperty name . fmap (ioProperty . runSessionWithApp)

This is the same function, just with a more restricted type. It states that for any Arbitrary a, Show a, a test is a function that takes a as input and returns a Session prop. This restricts tests to take a single input value, which means that you'll have to write all those properties in tupled, uncurried form. You could relax that requirement by introducing a newtype and a type class with an instance that recursively enables curried functions. That's what Test.Hspec.Wai.QuickCheck does. I decided not to add that extra level of indirection, and instead living with having to write all my properties in tupled form.

The Functor f in the above, relaxed type, then, is in actual use the Reader functor. You'll see some examples next.

Properties #

You can now define some properties. Here's a simple example:

appProperty "responds with 404 when no reservation exists" $ \rid -> do
  actual <- get $ "/reservations/" <> toASCIIBytes rid
  assertStatus 404 actual

This is an inlined property, similar to how I inline HUnit tests in test lists.

First, notice that the property is written as a lambda expression, which means that it fits the mould of a -> Session prop. The input value rid (reservationID) is a UUID value (for which an Arbitrary instance exists via quickcheck-instances).

While the test runs in the Session monad, the do notation makes actual an SResponse value that you can then assert with assertStatus (from Network.Wai.Test).

This property reproduces an interaction like this:

& curl -v http://localhost:8080/reservations/db38ac75-9ccd-43cc-864a-ce13e90a71d8
*   Trying ::1:8080...
* TCP_NODELAY set
*   Trying 127.0.0.1:8080...
* TCP_NODELAY set
* Connected to localhost (127.0.0.1) port 8080 (#0)
> GET /reservations/db38ac75-9ccd-43cc-864a-ce13e90a71d8 HTTP/1.1
> Host: localhost:8080
> User-Agent: curl/7.65.1
> Accept: */*
>
* Mark bundle as not supporting multiuse
< HTTP/1.1 404 Not Found
< Transfer-Encoding: chunked
< Date: Tue, 02 Jul 2019 18:09:51 GMT
< Server: Warp/3.2.27
<
* Connection #0 to host localhost left intact

The important result is that the status code is 404 Not Found, which is also what the property asserts.

If you need more than one input value to your property, you have to write the property in tupled form:

appProperty "fails when reservation is POSTed with invalid quantity" $ \
  (ValidReservation r, NonNegative q) -> do
  let invalid = r { reservationQuantity = negate q }
  actual <- postJSON "/reservations" $ encode invalid
  assertStatus 400 actual

This property still takes a single input, but that input is a tuple where the first element is a ValidReservation and the second element a NonNegative Int. The ValidReservation newtype wrapper ensures that r is a valid reservation record. This ensures that the property only exercises the path where the reservation quantity is zero or negative. It accomplishes this by negating q and replacing the reservationQuantity with that negative (or zero) number.

It then encodes (with aeson) the invalid reservation and posts it using the postJSON function.

Finally it asserts that the HTTP status code is 400 Bad Request.

Summary #

After having tried using Test.Hspec.Wai for some time, I decided to refactor my tests to QuickCheck and HUnit. Once I figured out how Network.Wai.Test works, the remaining work wasn't too difficult. While there's little written documentation for the modules, the types (as usual) act as documentation. Using the types, and looking a little at the underlying code, I was able to figure out how to use the test API.

You write tests against wai applications in the Session monad. You can then use runSession to turn the Session into an IO value.

A comprehensive code example showing how to implement a functional architecture in F#.

This article shows how to implement the picture archivist architecture described in a previous article. In short, the task is to move some image files to directories based on their date-taken metadata. The architectural idea is to load a directory structure from disk into an in-memory tree, manipulate that tree, and use the resulting tree to perform the desired actions:

Much of the program will manipulate the tree data, which is immutable.

The previous article showed how to implement the picture archivist architecture in Haskell. In this article, you'll see how to do it in F#. This is essentially a port of the Haskell code.

Tree #

You can start by defining a rose tree:

type Tree<'a, 'b> = Node of 'a * Tree<'a, 'b> list | Leaf of 'b

If you wanted to, you could put all the Tree code in a reusable library, because none of it is coupled to a particular application, such as moving pictures. You could also write a comprehensive test suite for the following functions, but in this article, I'll skip that.

Notice that this sort of tree explicitly distinguishes between internal and leaf nodes. This is necessary because you'll need to keep track of the directory names (the internal nodes), while at the same time you'll want to enrich the leaves with additional data - data that you can't meaningfully add to the internal nodes. You'll see this later in the article.

While I typically tend to define F# types outside of modules (so that you don't have to, say, prefix the type name with the module name - Tree.Tree is so awkward), the rest of the tree code goes into a module, including two helper functions:

module Tree =
    // 'b -> Tree<'a,'b>
    let leaf = Leaf
    
    // 'a -> Tree<'a,'b> list -> Tree<'a,'b>
    let node x xs = Node (x, xs)

The leaf function doesn't add much value, but the node function offers a curried alternative to the Node case constructor. That's occasionally useful.

The rest of the code related to trees is also defined in the Tree module, but I'm going to present it formatted as free-standing functions. If you're confused about the layout of the code, the entire code base is available on GitHub.

The rose tree catamorphism is this cata function:

// ('a -> 'c list -> 'c) -> ('b -> 'c) -> Tree<'a,'b> -> 'c
let rec cata fd ff = function
    | Leaf x -> ff x
    | Node (x, xs) -> xs |> List.map (cata fd ff) |> fd x

In the corresponding Haskell implementation of this architecture, I called this function foldTree, so why not retain that name? The short answer is that the naming conventions differ between Haskell and F#, and while I favour learning from Haskell, I still want my F# code to be as idiomatic as possible.

While I don't enforce that client code must use the Tree module name to access the functions within, I prefer to name the functions so that they make sense when used with qualified access. Having to write Tree.foldTree seems redundant. A more idiomatic name would be fold, so that you could write Tree.fold. The problem with that name, though, is that fold usually implies a list-biased fold (corresponding to foldl in Haskell), and I'll actually need that name for that particular purpose later.

So, cata it is.

In this article, tree functionality is (with one exception) directly or transitively implemented with cata.

Filtering trees #

It'll be useful to be able to filter the contents of a tree. For example, the picture archivist program will only move image files with valid metadata. This means that it'll need to filter out all files that aren't image files, as well as image files without valid metadata.

It turns out that it'll be useful to supply a function that throws away None values from a tree of option leaves. This is similar to List.choose, so I call it Tree.choose:

// ('a -> 'b option) -> Tree<'c,'a> -> Tree<'c,'b> option
let choose f = cata (fun x -> List.choose id >> node x >> Some) (f >> Option.map Leaf)

You may find the type of the function surprising. Why does it return a Tree option, instead of simply a Tree?

While List.choose simply returns a list, it can do this because lists can be empty. This Tree type, on the other hand, can't be empty. If the purpose of Tree.choose is to throw away all None values, then how do you return a tree from Leaf None?

You can't return a Leaf because you have no value to put in the leaf. Similarly, you can't return a Node because, again, you have no value to put in the node.

In order to handle this edge case, then, you'll have to return None:

> let l : Tree<string, int option> = Leaf None;;
val l : Tree<string,int option> = Leaf None

> Tree.choose id l;;
val it : Tree<string,int> option = None

If you have anything other than a None leaf, though, you'll get a proper tree, but wrapped in an option:

> Tree.node "Foo" [Leaf (Some 42); Leaf None; Leaf (Some 2112)] |> Tree.choose id;;
val it : Tree<string,int> option = Some (Node ("Foo",[Leaf 42; Leaf 2112]))

While the resulting tree is wrapped in a Some case, the leaves contain unwrapped values.

Bifunctor, functor, and folds #

Through its type class language feature, Haskell has formal definitions of functors, bifunctors, and other types of folds (list-biased catamorphisms). F# doesn't have a similar degree of formalism, which means that while you can still implement the corresponding functionality, you'll have to rely on conventions to make the functions recognisable.

It's straighforward to start with the bifunctor functionality:

// ('a -> 'b) -> ('c -> 'd) -> Tree<'a,'c> -> Tree<'b,'d>
let bimap f g = cata (f >> node) (g >> leaf)

This is, apart from the syntax differences, the same implementation as in Haskell. Based on bimap, you can also trivially implement mapNode and mapLeaf functions if you'd like, but you're not going to need those for the code in this article. You do need, however, a function that we could consider an alias of a hypothetical mapLeaf function:

// ('b -> 'c) -> Tree<'a,'b> -> Tree<'a,'c>
let map f = bimap id f

This makes Tree a functor.

It'll also be useful to reduce a tree to a potentially more compact value, so you can add some specialised folds:

// ('c -> 'a -> 'c) -> ('c -> 'b -> 'c) -> 'c -> Tree<'a,'b> -> 'c
let bifold f g z t =
    let flip f x y = f y x
    cata (fun x xs -> flip f x >> List.fold (>>) id xs) (flip g) t z
 
// ('a -> 'c -> 'c) -> ('b -> 'c -> 'c) -> Tree<'a,'b> -> 'c -> 'c
let bifoldBack f g t z = cata (fun x xs -> List.foldBack (<<) xs id >> f x) g t z

In an attempt to emulate the F# naming conventions, I named the functions as I did. There are similar functions in the List and Option modules, for instance. If you're comparing the F# code with the Haskell code in the previous article, Tree.bifold corresponds to bifoldl, and Tree.bifoldBack corresponds to bifoldr.

These enable you to implement folds over leaves only:

// ('c -> 'b -> 'c) -> 'c -> Tree<'a,'b> -> 'c
let fold f = bifold (fun x _ -> x) f
 
// ('b -> 'c -> 'c) -> Tree<'a,'b> -> 'c -> 'c
let foldBack f = bifoldBack (fun _ x -> x) f

These, again, enable you to implement another function that'll turn out to be useful in this article:

// ('b -> unit) -> Tree<'a,'b> -> unit
let iter f = fold (fun () x -> f x) ()

The picture archivist program isn't going to explicitly need all of these, but transitively, it will.

Moving pictures #

So far, all the code shown here could be in a general-purpose reusable library, since it contains no functionality specifically related to image files. The rest of the code in this article, however, will be specific to the program. I'll put the domain model code in another module that I call Archive. Later in the article, we'll look at how to load a tree from the file system, but for now, we'll just pretend that we have such a tree.

The major logic of the program is to create a destination tree based on a source tree. The leaves of the tree will have to carry some extra information apart from a file path, so you can introduce a specific type to capture that information:

type PhotoFile = { File : FileInfo; TakenOn : DateTime }

A PhotoFile not only contains the file path for an image file, but also the date the photo was taken. This date can be extracted from the file's metadata, but that's an impure operation, so we'll delegate that work to the start of the program. We'll return to that later.

Given a source tree of PhotoFile leaves, though, the program must produce a destination tree of files:

// string -> Tree<'a,PhotoFile> -> Tree<string,FileInfo>
let moveTo destination t =
    let dirNameOf (dt : DateTime) = sprintf "%d-%02d" dt.Year dt.Month
    let groupByDir pf m =
        let key = dirNameOf pf.TakenOn
        let dir = Map.tryFind key m |> Option.defaultValue []
        Map.add key (pf.File :: dir) m
    let addDir name files dirs =
        Tree.node name (List.map Leaf files) :: dirs
 
    let m = Tree.foldBack groupByDir t Map.empty
    Map.foldBack addDir m [] |> Tree.node destination

This moveTo function looks, perhaps, overwhelming, but it's composed of three conceptual steps:

1. Create a map of destination folders (m).
2. Create a list of branches from the map (Map.foldBack addDir m []).
3. Create a tree from the list (Tree.node destination).

The entire mapping step groups the PhotoFile values into a map of the type Map<string,FileInfo list>. All the image files taken in April 2014 are added to the list with the "2014-04" key, all the image files taken in July 2011 are added to the list with the "2011-07" key, and so on.

In the next step, the moveTo function converts the map to a list of trees. This will be the branches (or sub-directories) of the destination directory. Because of the desired structure of the destination tree, this is a list of shallow branches. Each node contains only leaves.

The only remaining step is to add that list of branches to a destination node. This is done by piping (|>) the list of sub-directories into Tree.node destination.

Since this is a pure function, it's easy to unit test. Just create some test cases and call the function. First, the test cases.

In this code base, I'm using xUnit.net 2.4.1, so I'll first create a set of test cases as a test-specific class:

type MoveToDestinationTestData () as this =
    inherit TheoryData<Tree<string, PhotoFile>, string, Tree<string, string>> ()
 
    let photoLeaf name (y, mth, d, h, m, s) =
        Leaf { File = FileInfo name; TakenOn = DateTime (y, mth, d, h, m, s) }
 
    do this.Add (
        photoLeaf "1" (2018, 11, 9, 11, 47, 17),
        "D",
        Node ( "D", [Node ("2018-11", [Leaf "1"])]))
    do this.Add (
        Node ("S", [photoLeaf "4" (1972, 6, 6, 16, 15, 0)]),
        "D",
        Node ("D", [Node ("1972-06", [Leaf "4"])]))
    do this.Add (
        Node ("S", [
            photoLeaf "L" (2002, 10, 12, 17, 16, 15);
            photoLeaf "J" (2007, 4, 21, 17, 18, 19)]),
        "D",
        Node ("D", [
            Node ("2002-10", [Leaf "L"]);
            Node ("2007-04", [Leaf "J"])]))
    do this.Add (
        Node ("1", [
            photoLeaf "a" (2010, 1, 12, 17, 16, 15);
            photoLeaf "b" (2010, 3, 12, 17, 16, 15);
            photoLeaf "c" (2010, 1, 21, 17, 18, 19)]),
        "2",
        Node ("2", [
            Node ("2010-01", [Leaf "a"; Leaf "c"]);
            Node ("2010-03", [Leaf "b"])]))
    do this.Add (
        Node ("foo", [
            Node ("bar", [
                photoLeaf "a" (2010, 1, 12, 17, 16, 15);
                photoLeaf "b" (2010, 3, 12, 17, 16, 15);
                photoLeaf "c" (2010, 1, 21, 17, 18, 19)]);
            Node ("baz", [
                photoLeaf "d" (2010, 3, 1, 2, 3, 4);
                photoLeaf "e" (2011, 3, 4, 3, 2, 1)])]),
        "qux",
        Node ("qux", [
            Node ("2010-01", [Leaf "a"; Leaf "c"]);
            Node ("2010-03", [Leaf "b"; Leaf "d"]);
            Node ("2011-03", [Leaf "e"])]))

That looks like a lot of code, but is really just a list of test cases. Each test case is a triple of a source tree, a destination directory name, and an expected result (another tree).

The test itself, on the other hand, is compact:

[<Theory; ClassData(typeof<MoveToDestinationTestData>)>]
let ``Move to destination`` source destination expected =
    let actual = Archive.moveTo destination source
    expected =! Tree.map string actual

The =! operator comes from Unquote and means something like must equal. It's an assertion that will throw an exception if expected isn't equal to Tree.map string actual.

The reason that the assertion maps actual to a tree of strings is that actual is a Tree<string,FileInfo>, but FileInfo doesn't have structural equality. So either I had to implement a test-specific equality comparer for FileInfo (and for Tree<string,FileInfo>), or map the tree to something with proper equality, such as a string. I chose the latter.

Calculating moves #

One pure step remains. The result of calling the moveTo function is a tree with the desired structure. In order to actually move the files, though, for each file you'll need to keep track of both the source path and the destination path. To make that explicit, you can define a type for that purpose:

type Move = { Source : FileInfo; Destination : FileInfo }

A Move is simply a data structure. Contrast this with typical object-oriented design, where it would be a (possibly polymorphic) method on an object. In functional programming, you'll regularly model intent with a data structure. As long as intents remain data, you can easily manipulate them, and once you're done with that, you can run an interpreter over your data structure to perform the work you want accomplished.

The unit test cases for the moveTo function suggest that file names are local file names like "L", "J", "a", and so on. That was only to make the tests as compact as possible, since the function actually doesn't manipulate the specific FileInfo objects.

In reality, the file names will most likely be longer, and they could also contain the full path, instead of the local path: "C:\foo\bar\a.jpg".

If you call moveTo with a tree where each leaf has a fully qualified path, the output tree will have the desired structure of the destination tree, but the leaves will still contain the full path to each source file. That means that you can calculate a Move for each file:

// Tree<string,FileInfo> -> Tree<string,Move>
let calculateMoves =
    let replaceDirectory (f : FileInfo) d =
        FileInfo (Path.Combine (d, f.Name))
    let rec imp path = function
        | Leaf x ->
            Leaf { Source = x; Destination = replaceDirectory x path }
        | Node (x, xs) ->
            let newNPath = Path.Combine (path, x)
            Tree.node newNPath (List.map (imp newNPath) xs)
    imp ""

This function takes as input a Tree<string,FileInfo>, which is compatible with the output of moveTo. It returns a Tree<string,Move>, i.e. a tree where the leaves are Move values.

Earlier, I wrote that you can implement desired Tree functionality with the cata function, but that was a simplification. If you can implement the functionality of calculateMoves with cata, I don't know how. You can, however, implement it using explicit pattern matching and simple recursion.

The imp function builds up a file path as it recursively negotiates the tree. All Leaf nodes are converted to a Move value using the leaf node's current FileInfo value as the Source, and the path to figure out the desired Destination.

This code is still easy to unit test. First, test cases:

type CalculateMovesTestData () as this =
    inherit TheoryData<Tree<string, FileInfo>, Tree<string, (string * string)>> ()
 
    do this.Add (Leaf (FileInfo "1"), Leaf ("1", "1"))
    do this.Add (
        Node ("a", [Leaf (FileInfo "1")]),
        Node ("a", [Leaf ("1", Path.Combine ("a", "1"))]))
    do this.Add (
        Node ("a", [Leaf (FileInfo "1"); Leaf (FileInfo "2")]),
        Node ("a", [
            Leaf ("1", Path.Combine ("a", "1"));
            Leaf ("2", Path.Combine ("a", "2"))]))
    do this.Add (
        Node ("a", [
            Node ("b", [
                Leaf (FileInfo "1");
                Leaf (FileInfo "2")]);
            Node ("c", [
                Leaf (FileInfo "3")])]),
        Node ("a", [
            Node (Path.Combine ("a", "b"), [
                Leaf ("1", Path.Combine ("a", "b", "1"));
                Leaf ("2", Path.Combine ("a", "b", "2"))]);
            Node (Path.Combine ("a", "c"), [
                Leaf ("3", Path.Combine ("a", "c", "3"))])]))

The test cases in this parametrised test are tuples of an input tree and the expected tree. For each test case, the test calls the Archive.calculateMoves function with tree and asserts that the actual tree is equal to the expected tree:

[<Theory; ClassData(typeof<CalculateMovesTestData>)>]
let ``Calculate moves`` tree expected =
    let actual = Archive.calculateMoves tree
    expected =! Tree.map (fun m -> (m.Source.ToString (), m.Destination.ToString ())) actual

Again, the test maps FileInfo objects to strings to support easy comparison.

That's all the pure code you need in order to implement the desired functionality. Now you only need to write some code that loads a tree from disk, and imprints a destination tree to disk, as well as the code that composes it all.

Loading a tree from disk #

The remaining code in this article is impure. You could put it in dedicated modules, but for this program, you're only going to need three functions and a bit of composition code, so you could also just put it all in the Program module. That's what I did.

To load a tree from disk, you'll need a root directory, under which you load the entire tree. Given a directory path, you read a tree using a recursive function like this:

// string -> Tree<string,string>
let rec readTree path =
    if File.Exists path
    then Leaf path
    else
        let dirsAndFiles = Directory.EnumerateFileSystemEntries path
        let branches = Seq.map readTree dirsAndFiles |> Seq.toList
        Node (path, branches)

This recursive function starts by checking whether the path is a file that exists. If it does, the path is a file, so it creates a new Leaf with that path.

If path isn't a file, it's a directory. In that case, use Directory.EnumerateFileSystemEntries to enumerate all the directories and files in that directory, and map all those directory entries recursively. That produces all the branches for the current node. Finally, return a new Node with the path and the branches.

Loading metadata #

The readTree function only produces a tree with string leaves, while the program requires a tree with PhotoFile leaves. You'll need to read the Exif metadata from each file and enrich the tree with the date-taken data.

In this code base, I've written a little Photo module to extract the desired metadata from an image file. I'm not going to list all the code here; if you're interested, the code is available on GitHub. The Photo module enables you to write an impure operation like this:

// FileInfo -> PhotoFile option
let readPhoto file =
    Photo.extractDateTaken file
    |> Option.map (fun dateTaken -> { File = file; TakenOn = dateTaken })

This operation can fail for various reasons:

• The file may not exist.
• The file exists, but has no metadata.
• The file has metadata, but no date-taken metadata.
• The date-taken metadata string is malformed.

Writing a tree to disk #

The above calculateMoves function creates a Tree<string,Move>. The final piece of impure code you'll need to write is an operation that traverses such a tree and executes each Move.

// Tree<'a,Move> -> unit
let writeTree t =
    let copy m =
        Directory.CreateDirectory m.Destination.DirectoryName |> ignore
        m.Source.CopyTo m.Destination.FullName |> ignore
        printfn "Copied to %s" m.Destination.FullName
    let compareFiles m =
        let sourceStream = File.ReadAllBytes m.Source.FullName
        let destinationStream = File.ReadAllBytes m.Destination.FullName
        sourceStream = destinationStream
    let move m =
        copy m
        if compareFiles m then m.Source.Delete ()
    Tree.iter move t

The writeTree function traverses the input tree, and for each Move, it first copies the file, then it verifies that the copy was successful, and finally, if that's the case, it deletes the source file.

Composition #

You can now compose an impure-pure-impure sandwich from all the Lego pieces:

// string -> string -> unit
let movePhotos source destination =
    let sourceTree = readTree source |> Tree.map FileInfo
    let photoTree = Tree.choose readPhoto sourceTree
    let destinationTree =
        Option.map (Archive.moveTo destination >> Archive.calculateMoves) photoTree
    Option.iter writeTree destinationTree

First, you load the sourceTree using the readTree operation. This returns a Tree<string,string>, so map the leaves to FileInfo objects. You then load the image metatadata by traversing sourceTree with Tree.choose readPhoto. Each call to readPhoto produces a PhotoFile option, so this is where you want to use Tree.choose to throw all the None values away.

Those two lines of code constitute the initial impure step of the sandwich (yes: mixed metaphors, I know).

The pure part of the sandwich is the composition of the pure functions moveTo and calculateMoves. Since photoTree is a Tree<string,PhotoFile> option, you'll need to perform that transformation inside of Option.map. The resulting destinationTree is a Tree<string,Move> option.

The final, impure step of the sandwich, then, is to apply all the moves with writeTree.

Execution #

The movePhotos operation takes source and destination arguments. You could hypothetically call it from a rich client or a background process, but here I'll just call if from a command-line program. The main operation will have to parse the input arguments and call movePhotos:

[<EntryPoint>]
let main argv =
    match argv with
    | [|source; destination|] -> movePhotos source destination
    | _ -> printfn "Please provide source and destination directories as arguments."
    0 // return an integer exit code

You could write more sophisticated parsing of the program arguments, but that's not the topic of this article, so I only wrote the bare minimum required to get the program working.

You can now compile and run the program:

$ ./ArchivePictures "C:\Users\mark\Desktop\Test" "C:\Users\mark\Desktop\Test-Out"
Copied to C:\Users\mark\Desktop\Test-Out\2003-04\2003-04-29 15.11.50.jpg
Copied to C:\Users\mark\Desktop\Test-Out\2011-07\2011-07-10 13.09.36.jpg
Copied to C:\Users\mark\Desktop\Test-Out\2014-04\2014-04-18 14.05.02.jpg
Copied to C:\Users\mark\Desktop\Test-Out\2014-04\2014-04-17 17.11.40.jpg
Copied to C:\Users\mark\Desktop\Test-Out\2014-05\2014-05-23 16.07.20.jpg
Copied to C:\Users\mark\Desktop\Test-Out\2014-06\2014-06-21 16.48.40.jpg
Copied to C:\Users\mark\Desktop\Test-Out\2014-06\2014-06-30 15.44.52.jpg
Copied to C:\Users\mark\Desktop\Test-Out\2016-05\2016-05-01 09.25.23.jpg
Copied to C:\Users\mark\Desktop\Test-Out\2017-08\2017-08-22 19.53.28.jpg

This does indeed produce the expected destination directory structure.

It's always nice when something turns out to work in practice, as well as in theory.

Summary #

Functional software architecture involves separating pure from impure code so that no pure functions invoke impure operations. Often, you can achieve that with what I call the impure-pure-impure sandwich architecture. In this example, you saw how to model the file system as a tree. This enables you to separate the impure file interactions from the pure program logic.

Comments

A comprehensive code example showing how to implement a functional architecture in Haskell.

This article shows how to implement the picture archivist architecture described in the previous article. In short, the task is to move some image files to directories based on their date-taken metadata. The architectural idea is to load a directory structure from disk into an in-memory tree, manipulate that tree, and use the resulting tree to perform the desired actions:

Much of the program will manipulate the tree data, which is immutable.

Tree #

You can start by defining a rose tree:

data Tree a b = Node a [Tree a b] | Leaf b deriving (Eq, Show, Read)

If you wanted to, you could put all the Tree code in a reusable library, because none of it is coupled to a particular application, such as moving pictures. You could also write a comprehensive test suite for the following functions, but in this article, I'll skip that.

Notice that this sort of tree explicitly distinguishes between internal and leaf nodes. This is necessary because you'll need to keep track of the directory names (the internal nodes), while at the same time you'll want to enrich the leaves with additional data - data that you can't meaningfully add to the internal nodes. You'll see this later in the article.

The rose tree catamorphism is this foldTree function:

foldTree :: (a -> [c] -> c) -> (b -> c) -> Tree a b -> c
foldTree  _ fl (Leaf x) = fl x
foldTree fn fl (Node x xs) = fn x $ foldTree fn fl <$> xs

Sometimes I name the catamorphism cata, sometimes something like tree, but using a library like Data.Tree as another source of inspiration, in this article I chose to name it foldTree.

In this article, tree functionality is (with one exception) directly or transitively implemented with foldTree.

Filtering trees #

It'll be useful to be able to filter the contents of a tree. For example, the picture archivist program will only move image files with valid metadata. This means that it'll need to filter out all files that aren't image files, as well as image files without valid metadata.

It turns out that it'll be useful to supply a function that throws away Nothing values from a tree of Maybe leaves. This is similar to the catMaybes function from Data.Maybe, so I call it catMaybeTree:

catMaybeTree :: Tree a (Maybe b) -> Maybe (Tree a b)
catMaybeTree = foldTree (\x -> Just . Node x . catMaybes) (fmap Leaf)

You may find the type of the function surprising. Why does it return a Maybe Tree, instead of simply a Tree? And if you accept the type as given, isn't this simply the sequence function?

While catMaybes simply returns a list, it can do this because lists can be empty. This Tree type, on the other hand, can't be empty. If the purpose of catMaybeTree is to throw away all Nothing values, then how do you return a tree from Leaf Nothing?

You can't return a Leaf because you have no value to put in the leaf. Similarly, you can't return a Node because, again, you have no value to put in the node.

In order to handle this edge case, then, you'll have to return Nothing:

Prelude Tree> catMaybeTree $ Leaf Nothing
Nothing

Isn't this the same as sequence, then? It's not, because sequence short-circuits all data, as this list example shows:

Prelude> sequence [Just 42, Nothing, Just 2112]
Nothing

Contrast this with the behaviour of catMaybes:

Prelude Data.Maybe> catMaybes [Just 42, Nothing, Just 2112]
[42,2112]

You've yet to see the Traversable instance for Tree, but it behaves in the same way:

Prelude Tree> sequence $ Node "Foo" [Leaf (Just 42), Leaf Nothing, Leaf (Just 2112)]
Nothing

The catMaybeTree function, on the other hand, returns a filtered tree:

Prelude Tree> catMaybeTree $ Node "Foo" [Leaf (Just 42), Leaf Nothing, Leaf (Just 2112)]
Just (Node "Foo" [Leaf 42,Leaf 2112])

While the resulting tree is wrapped in a Just case, the leaves contain unwrapped values.

Instances #

The article about the rose tree catamorphism already covered how to add instances of Bifunctor, Bifoldable, and Bitraversable, so I'll give this only cursory treatment. Refer to that article for a more detailed treatment. The code that accompanies that article also has QuickCheck properties that verify the various laws associated with those instances. Here, I'll just list the instances without further comment:

instance Bifunctor Tree where
  bimap f s = foldTree (Node . f) (Leaf . s)
 
instance Bifoldable Tree where
  bifoldMap f = foldTree (\x xs -> f x <> mconcat xs)
 
instance Bitraversable Tree where
  bitraverse f s =
    foldTree (\x xs -> Node <$> f x <*> sequenceA xs) (fmap Leaf . s)
 
instance Functor (Tree a) where
  fmap = second
 
instance Foldable (Tree a) where
  foldMap = bifoldMap mempty
 
instance Traversable (Tree a) where
  sequenceA = bisequenceA . first pure

The picture archivist program isn't going to explicitly need all of these, but transitively, it will.

Moving pictures #

So far, all the code shown here could be in a general-purpose reusable library, since it contains no functionality specifically related to image files. The rest of the code in this article, however, will be specific to the program. I'll put the domain model code in another module and import some functionality:

module Archive where
 
import Data.Time
import Text.Printf
import System.FilePath
import qualified Data.Map.Strict as Map
import Tree

Notice that Tree is one of the imported modules.

Later, we'll look at how to load a tree from the file system, but for now, we'll just pretend that we have such a tree.

The major logic of the program is to create a destination tree based on a source tree. The leaves of the tree will have to carry some extra information apart from a file path, so you can introduce a specific type to capture that information:

data PhotoFile =
  PhotoFile { photoFileName :: FilePath, takenOn :: LocalTime }
  deriving (Eq, Show, Read)

A PhotoFile not only contains the file path for an image file, but also the date the photo was taken. This date can be extracted from the file's metadata, but that's an impure operation, so we'll delegate that work to the start of the program. We'll return to that later.

Given a source tree of PhotoFile leaves, though, the program must produce a destination tree of files:

moveTo :: (Foldable t, Ord a, PrintfType a) => a -> t PhotoFile -> Tree a FilePath
moveTo destination =
  Node destination . Map.foldrWithKey addDir [] . foldr groupByDir Map.empty
  where
    dirNameOf (LocalTime d _) =
      let (y, m, _) = toGregorian d in printf "%d-%02d" y m
    groupByDir (PhotoFile fileName t) =
      Map.insertWith (++) (dirNameOf t) [fileName]
    addDir name files dirs = Node name (Leaf <$> files) : dirs

This moveTo function looks, perhaps, overwhelming, but it's composed of only three steps:

1. Create a map of destination folders (foldr groupByDir Map.empty).
2. Create a list of branches from the map (Map.foldrWithKey addDir []).
3. Create a tree from the list (Node destination).

Notice that this function works with any Foldable data container, so it'd work with lists and other data structures besides trees.

The moveTo function starts by folding the input data into a map. The map is keyed by the directory name, which is formatted by the dirNameOf function. This function takes a LocalTime as input and formats it to a YYYY-MM format. For example, December 20, 2018 becomes "2018-12".

The entire mapping step groups the PhotoFile values into a map of the type Map a [FilePath]. All the image files taken in April 2014 are added to the list with the "2014-04" key, all the image files taken in July 2011 are added to the list with the "2011-07" key, and so on.

In the next step, the moveTo function converts the map to a list of trees. This will be the branches (or sub-directories) of the destination directory. Because of the desired structure of the destination tree, this is a list of shallow branches. Each node contains only leaves.

The only remaining step is to add that list of branches to a destination node.

Since this is a pure function, it's easy to unit test. Just create some input values and call the function:

"Move to destination" ~: do
  (source, destination, expected) <-
    [
      ( Leaf $ PhotoFile "1" $ lt 2018 11 9 11 47 17
      , "D"
      , Node "D" [Node "2018-11" [Leaf "1"]])
      ,
      ( Node "S" [
          Leaf $ PhotoFile "4" $ lt 1972 6 6 16 15 00]
      , "D"
      , Node "D" [Node "1972-06" [Leaf "4"]])
      ,
      ( Node "S" [
          Leaf $ PhotoFile "L" $ lt 2002 10 12 17 16 15,
          Leaf $ PhotoFile "J" $ lt 2007 4 21 17 18 19]
      , "D"
      , Node "D" [Node "2002-10" [Leaf "L"], Node "2007-04" [Leaf "J"]])
      ,
      ( Node "1" [
          Leaf $ PhotoFile "a" $ lt 2010 1 12 17 16 15,
          Leaf $ PhotoFile "b" $ lt 2010 3 12 17 16 15,
          Leaf $ PhotoFile "c" $ lt 2010 1 21 17 18 19]
      , "2"
      , Node "2" [
          Node "2010-01" [Leaf "a", Leaf "c"],
          Node "2010-03" [Leaf "b"]])
      ,
      ( Node "foo" [
          Node "bar" [
            Leaf $ PhotoFile "a" $ lt 2010 1 12 17 16 15,
            Leaf $ PhotoFile "b" $ lt 2010 3 12 17 16 15,
            Leaf $ PhotoFile "c" $ lt 2010 1 21 17 18 19],
          Node "baz" [
            Leaf $ PhotoFile "d" $ lt 2010 3 1 2 3 4,
            Leaf $ PhotoFile "e" $ lt 2011 3 4 3 2 1
          ]]
      , "qux"
      , Node "qux" [
          Node "2010-01" [Leaf "a", Leaf "c"],
          Node "2010-03" [Leaf "b", Leaf "d"],
          Node "2011-03" [Leaf "e"]])
    ]
  let actual = moveTo destination source
  return $ expected ~=? actual

This is an inlined parametrised HUnit test. While it looks like a big unit test, it still follows my test formatting heuristic. There's only three expressions, but the arrange expression is big because it creates a list of test cases.

Each test case is a triple of a source tree, a destination directory name, and an expected result. In order to make the test data code more compact, it utilises this test-specific helper function:

lt y mth d h m s = LocalTime (fromGregorian y mth d) (TimeOfDay h m s)

For each test case, the test calls the moveTo function with the destination directory name and the source tree. It then asserts that the expected value is equal to the actual value.

Calculating moves #

One pure step remains. The result of calling the moveTo function is a tree with the desired structure. In order to actually move the files, though, for each file you'll need to keep track of both the source path and the destination path. To make that explicit, you can define a type for that purpose:

data Move =
  Move { sourcePath :: FilePath, destinationPath :: FilePath }
  deriving (Eq, Show, Read)

A Move is simply a data structure. Contrast this with typical object-oriented design, where it would be a (possibly polymorphic) method on an object. In functional programming, you'll regularly model intent with a data structure. As long as intents remain data, you can easily manipulate them, and once you're done with that, you can run an interpreter over your data structure to perform the work you want accomplished.

The unit test cases for the moveTo function suggest that file names are local file names like "L", "J", "a", and so on. That was only to make the tests as compact as possible, since the function actually doesn't manipulate the specific FilePath values.

In reality, the file names will most likely be longer, and they could also contain the full path, instead of the local path: "C:\foo\bar\a.jpg".

If you call moveTo with a tree where each leaf has a fully qualified path, the output tree will have the desired structure of the destination tree, but the leaves will still contain the full path to each source file. That means that you can calculate a Move for each file:

calculateMoves :: Tree FilePath FilePath -> Tree FilePath Move
calculateMoves = imp ""
  where imp path    (Leaf x) = Leaf $ Move x $ replaceDirectory x path
        imp path (Node x xs) = Node (path </> x) $ imp (path </> x) <$> xs

This function takes as input a Tree FilePath FilePath, which is compatible with the output of moveTo. It returns a Tree FilePath Move, i.e. a tree where the leaves are Move values.

To be fair, returning a tree is overkill. A [Move] (list of moves) would have been just as useful, but in this article, I'm trying to describe how to write code with a functional architecture. In the overview article, I explained how you can model a file system using a rose tree, and in order to emphasise that point, I'll stick with that model a little while longer.

Earlier, I wrote that you can implement desired Tree functionality with the foldTree function, but that was a simplification. If you can implement the functionality of calculateMoves with foldTree, I don't know how. You can, however, implement it using explicit pattern matching and simple recursion.

The imp function builds up a file path (using the </> path combinator) as it recursively negotiates the tree. All Leaf nodes are converted to a Move value using the leaf node's current FilePath value as the sourcePath, and the path to figure out the desired destinationPath.

This code is still easy to unit test:

"Calculate moves" ~: do
  (tree, expected) <-
    [
      (Leaf "1", Leaf $ Move "1" "1"),
      (Node "a" [Leaf "1"], Node "a" [Leaf $ Move "1" $ "a" </> "1"]),
      (Node "a" [Leaf "1", Leaf "2"], Node "a" [
        Leaf $ Move "1" $ "a" </> "1",
        Leaf $ Move "2" $ "a" </> "2"]),
      (Node "a" [Node "b" [Leaf "1", Leaf "2"], Node "c" [Leaf "3"]],
       Node "a" [
         Node ("a" </> "b") [
           Leaf $ Move "1" $ "a" </> "b" </> "1",
           Leaf $ Move "2" $ "a" </> "b" </> "2"],
         Node ("a" </> "c") [
           Leaf $ Move "3" $ "a" </> "c" </> "3"]])
    ]
  let actual = calculateMoves tree
  return $ expected ~=? actual

The test cases in this parametrised test are tuples of an input tree and the expected tree. For each test case, the test calls the calculateMoves function with tree and asserts that the actual tree is equal to the expected tree.

That's all the pure code you need in order to implement the desired functionality. Now you only need to write some code that loads a tree from disk, and imprints a destination tree to disk, as well as the code that composes it all.

Loading a tree from disk #

The remaining code in this article is impure. You could put it in dedicated modules, but for this program, you're only going to need three functions and a bit of composition code, so you could also just put it all in the Main module. That's what I did.

To load a tree from disk, you'll need a root directory, under which you load the entire tree. Given a directory path, you read a tree using a recursive function like this:

readTree :: FilePath -> IO (Tree FilePath FilePath)
readTree path = do
  isFile <- doesFileExist path
  if isFile
    then return $ Leaf path
    else do
      dirsAndfiles <- listDirectory path
      let paths = fmap (path </>) dirsAndfiles
      branches <- traverse readTree paths
      return $ Node path branches

This recursive function starts by checking whether the path is a file or a directory. If it's a file, it creates a new Leaf with that FilePath.

If path isn't a file, it's a directory. In that case, use listDirectory to enumerate all the directories and files in that directory. These are only local names, so prefix them with path to create full paths, then traverse all those directory entries recursively. That produces all the branches for the current node. Finally, return a new Node with the path and the branches.

Loading metadata #

The readTree function only produces a tree with FilePath leaves, while the program requires a tree with PhotoFile leaves. You'll need to read the Exif metadata from each file and enrich the tree with the date-taken data.

In this code base, I've used the hsexif library for this. That enables you to write an impure operation like this:

readPhoto :: FilePath -> IO (Maybe PhotoFile)
readPhoto path = do
  exifData <- parseFileExif path
  let dateTaken = either (const Nothing) Just exifData >>= getDateTimeOriginal
  return $ PhotoFile path <$> dateTaken

This operation can fail for various reasons:

• The file may not exist.
• The file exists, but has no metadata.
• The file has metadata, but no date-taken metadata.
• The date-taken metadata string is malformed.

When you traverse a Tree FilePath FilePath with readPhoto, you'll get a Tree FilePath (Maybe PhotoFile). That's when you'll need catMaybeTree. You'll see this soon.

Writing a tree to disk #

The above calculateMoves function creates a Tree FilePath Move. The final piece of impure code you'll need to write is an operation that traverses such a tree and executes each Move.

applyMoves :: Foldable t => t Move -> IO ()
applyMoves = traverse_ move
  where
    move m = copy m >> compareFiles m >>= deleteSource
    copy (Move s d) = do
      createDirectoryIfMissing True $ takeDirectory d
      copyFileWithMetadata s d
      putStrLn $ "Copied to " ++ show d
    compareFiles m@(Move s d) = do
      sourceBytes <- B.readFile s
      destinationBytes <- B.readFile d
      return $ if sourceBytes == destinationBytes then Just m else Nothing
    deleteSource           Nothing = return ()
    deleteSource (Just (Move s _)) = removeFile s

As I wrote above, a tree of Move values is, to be honest, overkill. Any Foldable container will do, as the applyMoves operation demonstrates. It traverses the data structure, and for each Move, it first copies the file, then it verifies that the copy was successful, and finally, if that's the case, it deletes the source file.

All of the operations invoked by these three steps are defined in various libraries part of the base GHC installation. You're welcome to peruse the source code repository if you're interested in the details.

Composition #

You can now compose an impure-pure-impure sandwich from all the Lego pieces:

movePhotos :: FilePath -> FilePath -> IO ()
movePhotos source destination = fmap fold $ runMaybeT $ do
  sourceTree <- lift $ readTree source
  photoTree <- MaybeT $ catMaybeTree <$> traverse readPhoto sourceTree
  let destinationTree = calculateMoves $ moveTo destination photoTree
  lift $ applyMoves destinationTree

First, you load the sourceTree using the readTree operation. This is a Tree FilePath FilePath value, because the code is written in do notation, and the context is MaybeT IO (). You then load the image metatadata by traversing sourceTree with readPhoto. This produces a Tree FilePath (Maybe PhotoFile) that you then filter with catMaybeTree. Again, because of do notation and monad transformer shenanigans, photoTree is a Tree FilePath PhotoFile value.

Those two lines of code is the initial impure step of the sandwich (yes: mixed metaphors, I know).

The pure part of the sandwich is the composition of the pure functions moveTo and calculateMoves. The result is a Tree FilePath Move value.

The final, impure step of the sandwich, then, is to applyMoves.

Execution #

The movePhotos operation takes source and destination arguments. You could hypothetically call it from a rich client or a background process, but here I'll just call if from a command-line program. The main operation will have to parse the input arguments and call movePhotos:

main :: IO ()
main = do
  args <- getArgs
  case args of
    [source, destination] -> movePhotos source destination
    _ -> putStrLn "Please provide source and destination directories as arguments."

You could write more sophisticated parsing of the program arguments, but that's not the topic of this article, so I only wrote the bare minimum required to get the program working.

You can now compile and run the program:

$ ./archpics "C:\Users\mark\Desktop\Test" "C:\Users\mark\Desktop\Test-Out"
Copied to "C:\\Users\\mark\\Desktop\\Test-Out\\2003-04\\2003-04-29 15.11.50.jpg"
Copied to "C:\\Users\\mark\\Desktop\\Test-Out\\2011-07\\2011-07-10 13.09.36.jpg"
Copied to "C:\\Users\\mark\\Desktop\\Test-Out\\2014-04\\2014-04-17 17.11.40.jpg"
Copied to "C:\\Users\\mark\\Desktop\\Test-Out\\2014-04\\2014-04-18 14.05.02.jpg"
Copied to "C:\\Users\\mark\\Desktop\\Test-Out\\2014-05\\2014-05-23 16.07.20.jpg"
Copied to "C:\\Users\\mark\\Desktop\\Test-Out\\2014-06\\2014-06-30 15.44.52.jpg"
Copied to "C:\\Users\\mark\\Desktop\\Test-Out\\2014-06\\2014-06-21 16.48.40.jpg"
Copied to "C:\\Users\\mark\\Desktop\\Test-Out\\2016-05\\2016-05-01 09.25.23.jpg"
Copied to "C:\\Users\\mark\\Desktop\\Test-Out\\2017-08\\2017-08-22 19.53.28.jpg"

This does indeed produce the expected destination directory structure.

It's always nice when something turns out to work in practice, as well as in theory.

Summary #

Functional software architecture involves separating pure from impure code so that no pure functions invoke impure operations. Often, you can achieve that with what I call the impure-pure-impure sandwich architecture. In this example, you saw how to model the file system as a tree. This enables you to separate the impure file interactions from the pure program logic.

The Haskell type system enforces the functional interaction law, which implies that the architecture is, indeed, properly functional. Other languages, like F#, don't enforce the law via the compiler, but that doesn't prevent you doing functional programming. Now that we've verified that the architecture is, indeed, functional, we can port it to F#.

Next: Picture archivist in F#.

Comments

A simple naming scheme for newtypes to add Arbitrary instances.

Naming is one of those recurring difficult problems in software development. How do you come up with good names?

I'm not aware of any general heuristic for that, but sometimes, in specific contexts, a naming scheme presents itself. Here's one.

Orphan instances #

When you write QuickCheck properties that involve your own custom types, you'll have to add Arbitrary instances for those types. As an example, here's a restaurant reservation record type:

data Reservation = Reservation
  { reservationId :: UUID
  , reservationDate :: LocalTime
  , reservationName :: String
  , reservationEmail :: String
  , reservationQuantity :: Int
  } deriving (Eq, Show, Read, Generic)

You can easily add an Arbitrary instance to such a type:

instance Arbitrary Reservation where
  arbitrary =
    liftM5 Reservation arbitrary arbitrary arbitrary arbitrary arbitrary

The type itself is part of your domain model, while the Arbitrary instance only belongs to your test code. You shouldn't add the Arbitrary instance to the domain model, but that means that you'll have to define the instance apart from the type definition. That, however, is an orphan instance, and the compiler will complain:

test\ReservationAPISpec.hs:31:1: warning: [-Worphans]
    Orphan instance: instance Arbitrary Reservation
    To avoid this
        move the instance declaration to the module of the class or of the type, or
        wrap the type with a newtype and declare the instance on the new type.
   |
31 | instance Arbitrary Reservation where
   | ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^...

Technically, this isn't a difficult problem to solve. The warning even suggests remedies. Moving the instance to the module that declares the type is, however, inappropriate, since test-specific instances don't belong in the domain model. Wrapping the type in a newtype is more appropriate, but what should you call the type?

Suppress the warning #

I had trouble coming up with good names for such newtype wrappers, so at first I decided to just suppress that particular compiler warning. I simply added the -fno-warn-orphans flag exclusively to my test code.

That solved the immediate problem, but I felt a little dirty. It's okay, though, because you're not supposed to reuse test libraries anyway, so the usual problems with orphan instances don't apply.

After having worked a little like this, however, it dawned on me that I needed more than one Arbitrary instance, and a naming scheme presented itself.

Naming scheme #

For some of the properties I wrote, I needed a valid Reservation value. In this case, valid means that the reservationQuantity is a positive number, and that the reservationDate is in the future. It seemed natural to signify these constraints with a newtype:

newtype ValidReservation = ValidReservation Reservation deriving (Eq, Show)
 
instance Arbitrary ValidReservation where
  arbitrary = do
    rid <- arbitrary
    d <- (\dt -> addLocalTime (getPositive dt) now2019) <$> arbitrary
    n <- arbitrary
    e <- arbitrary
    (Positive q) <- arbitrary
    return $ ValidReservation $ Reservation rid d n e q

The newtype is, naturally, called ValidReservation and can, for example, be used like this:

it "responds with 200 after reservation is added" $ WQC.property $ \
  (ValidReservation r) -> do
  _ <- postJSON "/reservations" $ encode r
  let actual = get $ "/reservations/" <> toASCIIBytes (reservationId r)
  actual `shouldRespondWith` 200

For the few properties where any Reservation goes, a name for a newtype now also suggests itself:

newtype AnyReservation = AnyReservation Reservation deriving (Eq, Show)
 
instance Arbitrary AnyReservation where
  arbitrary =
    AnyReservation <$>
    liftM5 Reservation arbitrary arbitrary arbitrary arbitrary arbitrary

The only use I've had for that particular instance so far, though, is to ensure that any Reservation correctly serialises to, and deserialises from, JSON:

it "round-trips" $ property $ \(AnyReservation r) -> do
  let json = encode r
  let actual = decode json
  actual `shouldBe` Just r

With those two newtype wrappers, I no longer have any orphan instances.

Summary #

A simple naming scheme for newtype wrappers for QuickCheck Arbitrary instances, then, is:

• If the instance is truly unbounded, prefix the wrapper name with Any
• If the instance only produces valid values, prefix the wrapper name with Valid

How do you model file systems in a functional manner, so that unit testing is enabled? An overview.

One of the many reasons that I like functional programming is that it's intrinsically testable. In object-oriented programming, you often have to jump through hoops to enable testing. This is also the case whenever you need to interact with the computer's file system. Just try to search the web for file system interface, or mock file system. I'm not going to give you any links, because I think such questions are XY problems. I don't think that the most common suggestions are proper solutions.

In functional programming, anyway, Dependency Injection isn't functional, because it makes everything impure. How, then, do you model the file system in such a way that it's pure, decoupled from the logic you'd like to add on top of it, and still has enough fidelity that you can perform most tasks?

You model the file system as a tree, or a forest.

File systems are hierarchies #

It should come as no surprise that file systems are hierarchies, or trees. Each logical drive is the root of a tree. Files are leaves, and directories are internal nodes. Does that sound familiar? That sounds like a rose tree.

Rose trees are immutable data structures. It doesn't get much more functional than that. Why not use a rose tree (or a forest) to model the file system?

What about interaction with the actual file system? Usually, when you encounter object-oriented attempts at decoupling an abstraction from the actual file system, you'll find polymorphic operations such as WriteAllText, GetFileSystemEntries, CreateDirectory, and so on. These would be the (mockable) methods that you have to implement, usually as Humble Objects.

If you, instead of a set of interfaces, model the file system as a forest, interacting with the actual file system is not even part of the abstraction. That's a typical shift of perspective from object-oriented design to functional programming.

In object-oriented design, you typically attempt to model data with behaviour. Sometimes that fits the underlying reality well, but in this case it doesn't. While you have file and directory objects with behaviour, the actual structure of a file system is implicit. It's hidden in the interactions between the objects.

By modelling the file system as a tree, you explicitly use the structure of the data. How you load a tree into program memory, or how you imprint a tree unto the file system isn't part of the abstraction. When it comes to input and output, you're free to do what you want.

Once you have a model of a directory structure in memory, you can manipulate it to your heart's content. Since rose trees are functors, you know that all transformations are structure-preserving. That means that you don't even need to write tests for those parts of your application.

You'll appreciate an example, I'm sure.

Picture archivist example #

As an example, I'll attempt to answer an old Code Review question. I already gave an answer in 2015, but I'm not so happy with it today as I was back then. The question is great, though, because it explicitly demonstrates how people have a hard time escaping the notion that abstraction is only available via interfaces or abstract base classes. In 2015, I had long since figured out that delegates (and thus functions) are anonymous interfaces, but I still hadn't figured out how to separate pure from impure behaviour.

The question's scenario is how to implement a small program that can inspect a collection of image files, extract the date-taken metadata from each file, and move the files to a new directory structure based on that information.

For example, you could have files organised in various directories according to motive.

You soon realise, however, that that archiving strategy is untenable, because what do you do if there's more than one type of motive in a picture? Instead, you decide to organise the files according to month and year.

Clearly, there's some input and output involved in this application, but there's also some logic that you'd like to unit test. You need to parse the metadata, figure out where to move each image file, filter out files that are not images, and so on.

Object-oriented picture archivist #

If you were to implement such a picture archivist program with an object-oriented design, you may use Dependency Injection so that you can 'mock' the file system during unit testing. A typical program might then work like this at run time:

The program has fine-grained, busy interaction with the file system (through a polymorphic interface). It'll typically read one file, load its metadata, decide where to put the file, and copy it there. Then it'll move on to the next file, although it might also do this in parallel. Throughout the program execution, there's input and output going on, which makes it difficult to isolate the pure from the impure code.

Even if you write a program like that in F#, it's hardly a functional architecture.

Such an architecture is, in theory, testable, but my experience is that if you attempt to reproduce such busy, fine-grained interaction with mocks and stubs, you're likely to end up with brittle tests.

Functional picture archivist #

In functional programming, you'll have to reject the notion of dependencies. Instead, you can often resort to the simple architecture I call an impure-pure-impure sandwich; here, specifically:

1. Load data from disk (impure)
2. Transform the data (pure)
3. Write data to disk (impure)

When the program starts, it loads data from disk into a tree. It then manipulates the in-memory model of the files in question, and once it's done, it traverses the entire tree and applies the changes.

This gives you a much clearer separation between the pure and impure parts of the code base. The pure part is bigger, and easier to unit test.

Example code #

This article gave you an overview of the functional architecture. In the next two articles, you'll see how to do this in practice. First, I'll implement the above architecture in Haskell, so that we know that if it works there, the architecture does, indeed, respect the functional interaction law.

Based on the Haskell implementation, you'll then see a port to F#.

• Picture archivist in Haskell
• Picture archivist in F#

Summary #

One of the hardest problems in transitioning from object-oriented programming to functional programming is that the design approach is so different. Many well-understood design patterns and principles don't translate easily. Dependency Injection is one of those. Often, you'll have to flip the model on its head, so to speak, before you can take it on in a functional manner.

While most object-oriented programmers would say that object-oriented design involves focusing on 'the nouns', in practice, it often revolves around interactions and behaviour. Sometimes, that's appropriate, but often, it's not.

Functional programming, in contrast, tends to take a more data-oriented perspective. Load some data, manipulate it, and publish it. If you can come up with an appropriate data structure for the data, you're probably on your way to implementing a functional architecture.

Next: Picture archivist in Haskell.

Rose trees form normal functors. A place-holder article for object-oriented programmers.

This article is an instalment in an article series about functors. As another article explains, a rose tree is a bifunctor. This makes it trivially a functor. As such, this article is mostly a place-holder to fit the spot in the functor table of contents, thereby indicating that rose trees are functors.

Since a rose tree is a bifunctor, it's actually not one, but two, functors. Many languages, C# included, are best equipped to deal with unambiguous functors. This is also true in Haskell, where you'd usally define the Functor instance over a bifunctor's right, or second, side. Likewise, in C#, you can make IRoseTree<N, L> a functor by implementing Select:

public static IRoseTree<N, L1> Select<N, L, L1>(
    this IRoseTree<N, L> source,
    Func<L, L1> selector)
{
    return source.SelectLeaf(selector);
}

This method simply delegates all implementation to the SelectLeaf method; it's just SelectLeaf by another name. It obeys the functor laws, since these are just specializations of the bifunctor laws, and we know that a rose tree is a proper bifunctor.

It would have been technically possible to instead implement a Select method by calling SelectNode, but it seems marginally more useful to enable syntactic sugar for mapping over the leaves.

Menu example #

As an example, imagine that you're defining part of a menu bar for an old-fashioned desktop application. Perhaps you're even loading the structure of the menu from a text file. Doing so, you could create a simple tree that represents the edit menu:

IRoseTree<string, string> editMenuTemplate =
    RoseTree.Node("Edit",
        RoseTree.Node("Find and Replace",
            new RoseLeaf<string, string>("Find"),
            new RoseLeaf<string, string>("Replace")),
        RoseTree.Node("Case",
            new RoseLeaf<string, string>("Upper"),
            new RoseLeaf<string, string>("Lower")),
        new RoseLeaf<string, string>("Cut"),
        new RoseLeaf<string, string>("Copy"),
        new RoseLeaf<string, string>("Paste"));

At this point, you have an IRoseTree<string, string>, so you might as well have used a 'normal' tree instead of a rose tree. The above template, however, is only a first step, because you have this Command class:

public class Command
{
    public Command(string name)
    {
        Name = name;
    }
 
    public string Name { get; }
 
    public virtual void Execute()
    {
    }
}

Apart from this base class, you also have classes that derive from it: FindCommand, ReplaceCommand, and so on. These classes override the Execute method by implenting find, replace, etc. functionality. Imagine that you also have a store or dictionary of these derived objects. This enables you to transform the template tree into a useful user menu:

IRoseTree<string, Command> editMenu =
    from name in editMenuTemplate
    select commandStore.Lookup(name);

Notice how this transforms only the leaves, using the command store's Lookup method. This example uses C# query syntax, because this is what the Select method enables, but you could also have written the translation by just calling the Select method.

The internal nodes in a menu have no behavious, so it makes little sense to attempt to turn them into Command objects as well. They're only there to provide structure to the menu. With a 'normal' tree, you wouldn't have been able to enrich only the leaves, while leaving the internal nodes untouched, but with a rose tree you can.

The above example uses the Select method (via query syntax) to translate the nodes, thereby providing a demonstration of how to use the rose tree as the functor it is.

Summary #

The Select doesn't implement any behaviour not already provided by SelectLeaf, but it enables C# query syntax. The C# compiler understands functors, but not bifunctors, so when you have a bifunctor, you might as well light up that language feature as well by adding a Select method.

Next: A Visitor functor.

A rose tree forms a bifunctor. An article for object-oriented developers.

This article is an instalment in an article series about bifunctors. While the overview article explains that there's essentially two practically useful bifunctors, here's a third one. rose trees.

Mapping both dimensions #

Like in the previous article on the Either bifunctor, I'll start by implementing the simultaneous two-dimensional translation SelectBoth:

public static IRoseTree<N1, L1> SelectBoth<N, N1, L, L1>(
    this IRoseTree<N, L> source,
    Func<N, N1> selectNode,
    Func<L, L1> selectLeaf)
{
    return source.Cata(
        node: (n, branches) => new RoseNode<N1, L1>(selectNode(n), branches),
        leaf: l => (IRoseTree<N1, L1>)new RoseLeaf<N1, L1>(selectLeaf(l)));
}

This article uses the previously shown Church-encoded rose tree and its catamorphism Cata.

In the leaf case, the l argument received by the lambda expression is an object of the type L, since the source tree is an IRoseTree<N, L> object; i.e. a tree with leaves of the type L and nodes of the type N. The selectLeaf argument is a function that converts an L object to an L1 object. Since l is an L object, you can call selectLeaf with it to produce an L1 object. You can use this resulting object to create a new RoseLeaf<N1, L1>. Keep in mind that while the RoseLeaf class requires two type arguments, it never requires an object of its N type argument, which means that you can create an object with any node type argument, including N1, even if you don't have an object of that type.

In the node case, the lambda expression receives two objects: n and branches. The n object has the type N, while the branches object has the type IEnumerable<IRoseTree<N1, L1>>. In other words, the branches have already been translated to the desired result type. That's how the catamorphism works. This means that you only have to figure out how to translate the N object n to an N1 object. The selectNode function argument can do that, so you can then create a new RoseNode<N1, L1> and return it.

This works as expected:

> var tree = RoseTree.Node("foo", new RoseLeaf<string, int>(42), new RoseLeaf<string, int>(1337));
> tree
RoseNode<string, int>("foo", IRoseTree<string, int>[2] { 42, 1337 })
> tree.SelectBoth(s => s.Length, i => i.ToString())
RoseNode<int, string>(3, IRoseTree<int, string>[2] { "42", "1337" })

This C# Interactive example shows how to convert a tree with internal string nodes and integer leaves to a tree of internal integer nodes and string leaves. The strings are converted to strings by counting their Length, while the integers are turned into strings using the standard ToString method available on all objects.

Mapping nodes #

When you have SelectBoth, you can trivially implement the translations for each dimension in isolation. For tuple bifunctors, I called these methods SelectFirst and SelectSecond, while for Either bifunctors, I chose to name them SelectLeft and SelectRight. Continuing the trend of naming the translations after what they translate, instead of their positions, I'll name the corresponding methods here SelectNode and SelectLeaf. In Haskell, the functions associated with Data.Bifunctor are always called first and second, but I see no reason to preserve such abstract naming in C#. In Haskell, these functions are part of the Bifunctor type class; the abstract names serve an actual purpose. This isn't the case in C#, so there's no reason to retain the abstract names. You might as well use names that communicate intent, which is what I've tried to do here.

If you want to map only the internal nodes, you can implement a SelectNode method based on SelectBoth:

public static IRoseTree<N1, L> SelectNode<N, N1, L>(
    this IRoseTree<N, L> source,
    Func<N, N1> selector)
{
    return source.SelectBoth(selector, l => l);
}

This simply uses the l => l lambda expression as an ad-hoc identity function, while passing selector as the selectNode argument to the SelectBoth method.

You can use this to map the above tree to a tree made entirely of numbers:

> var tree = RoseTree.Node("foo", new RoseLeaf<string, int>(42), new RoseLeaf<string, int>(1337));
> tree.SelectNode(s => s.Length)
RoseNode<int, int>(3, IRoseTree<int, int>[2] { 42, 1337 })

Such a tree is, incidentally, isomorphic to a 'normal' tree. It might be a good exercise, if you need one, to demonstrate the isormorphism by writing functions that convert a Tree<T> into an IRoseTree<T, T>, and vice versa.

Mapping leaves #

Similar to SelectNode, you can also trivially implement SelectLeaf:

public static IRoseTree<N, L1> SelectLeaf<N, L, L1>(
    this IRoseTree<N, L> source,
    Func<L, L1> selector)
{
    return source.SelectBoth(n => n, selector);
}

This is another one-liner calling SelectBoth, with the difference that the identity function n => n is passed as the first argument, instead of as the last. This ensures that only RoseLeaf values are mapped:

> var tree = RoseTree.Node("foo", new RoseLeaf<string, int>(42), new RoseLeaf<string, int>(1337));
> tree.SelectLeaf(i => i % 2 == 0)
RoseNode<string, bool>("foo", IRoseTree<string, bool>[2] { true, false })

In the above C# Interactive session, the leaves are mapped to Boolean values, indicating whether they're even or odd.

Identity laws #

Rose trees obey all the bifunctor laws. While it's formal work to prove that this is the case, you can get an intuition for it via examples. Often, I use a property-based testing library like FsCheck or Hedgehog to demonstrate (not prove) that laws hold, but in this article, I'll keep it simple and only cover each law with a parametrised test.

private static T Id<T>(T x) => x;
 
public static IEnumerable<object[]> BifunctorLawsData
{
    get
    {
        yield return new[] { new RoseLeaf<int, string>("") };
        yield return new[] { new RoseLeaf<int, string>("foo") };
        yield return new[] { RoseTree.Node<int, string>(42) };
        yield return new[] { RoseTree.Node(42, new RoseLeaf<int, string>("bar")) };
        yield return new[] { exampleTree };
    }
}
 
[Theory, MemberData(nameof(BifunctorLawsData))]
public void SelectNodeObeysFirstFunctorLaw(IRoseTree<int, string> t)
{
    Assert.Equal(t, t.SelectNode(Id));
}

This test uses xUnit.net's [Theory] feature to supply a small set of example input values. The input values are defined by the BifunctorLawsData property, since I'll reuse the same values for all the bifunctor law demonstration tests. The exampleTree object is the tree shown in Church-encoded rose tree.

The tests also use the identity function implemented as a private function called Id, since C# doesn't come equipped with such a function in the Base Class Library.

For all the IRoseTree<int, string> objects t, the test simply verifies that the original tree t is equal to the tree projected over the first axis with the Id function.

Likewise, the first functor law applies when translating over the second dimension:

[Theory, MemberData(nameof(BifunctorLawsData))]
public void SelectLeafObeysFirstFunctorLaw(IRoseTree<int, string> t)
{
    Assert.Equal(t, t.SelectLeaf(Id));
}

This is the same test as the previous test, with the only exception that it calls SelectLeaf instead of SelectNode.

Both SelectNode and SelectLeaf are implemented by SelectBoth, so the real test is whether this method obeys the identity law:

[Theory, MemberData(nameof(BifunctorLawsData))]
public void SelectBothObeysIdentityLaw(IRoseTree<int, string> t)
{
    Assert.Equal(t, t.SelectBoth(Id, Id));
}

Projecting over both dimensions with the identity function does, indeed, return an object equal to the input object.

Consistency law #

In general, it shouldn't matter whether you map with SelectBoth or a combination of SelectNode and SelectLeaf:

[Theory, MemberData(nameof(BifunctorLawsData))]
public void ConsistencyLawHolds(IRoseTree<int, string> t)
{
    DateTime f(int i) => new DateTime(i);
    bool g(string s) => string.IsNullOrWhiteSpace(s);
 
    Assert.Equal(t.SelectBoth(f, g), t.SelectLeaf(g).SelectNode(f));
    Assert.Equal(
        t.SelectNode(f).SelectLeaf(g),
        t.SelectLeaf(g).SelectNode(f));
}

This example creates two local functions f and g. The first function, f, creates a new DateTime object from an integer, using one of the DateTime constructor overloads. The second function, g, just delegates to string.IsNullOrWhiteSpace, although I want to stress that this is just an example. The law should hold for any two (pure) functions.

The test then verifies that you get the same result from calling SelectBoth as when you call SelectNode followed by SelectLeaf, or the other way around.

Composition laws #

The composition laws insist that you can compose functions, or translations, and that again, the choice to do one or the other doesn't matter. Along each of the axes, it's just the second functor law applied. This parametrised test demonstrates that the law holds for SelectNode:

[Theory, MemberData(nameof(BifunctorLawsData))]
public void SecondFunctorLawHoldsForSelectNode(IRoseTree<int, string> t)
{
    char f(bool b) => b ? 'T' : 'F';
    bool g(int i) => i % 2 == 0;
 
    Assert.Equal(
        t.SelectNode(x => f(g(x))),
        t.SelectNode(g).SelectNode(f));
}

Here, f is a local function that returns the the character 'T' for true, and 'F' for false; g is the even function. The second functor law states that mapping f(g(x)) in a single step is equivalent to first mapping over g and then map the result of that using f.

The same law applies if you fix the first dimension and translate over the second:

[Theory, MemberData(nameof(BifunctorLawsData))]
public void SecondFunctorLawHoldsForSelectLeaf(IRoseTree<int, string> t)
{
    bool f(int x) => x % 2 == 0;
    int g(string s) => s.Length;
 
    Assert.Equal(
        t.SelectLeaf(x => f(g(x))),
        t.SelectLeaf(g).SelectLeaf(f));
}

Here, f is the even function, whereas g is a local function that returns the length of a string. Again, the test demonstrates that the output is the same whether you map over an intermediary step, or whether you map using only a single step.

This generalises to the composition law for SelectBoth:

[Theory, MemberData(nameof(BifunctorLawsData))]
public void SelectBothCompositionLawHolds(IRoseTree<int, string> t)
{
    char f(bool b) => b ? 'T' : 'F';
    bool g(int x) => x % 2 == 0;
    bool h(int x) => x % 2 == 0;
    int i(string s) => s.Length;
 
    Assert.Equal(
        t.SelectBoth(x => f(g(x)), y => h(i(y))),
        t.SelectBoth(g, i).SelectBoth(f, h));
}

Again, whether you translate in one or two steps shouldn't affect the outcome.

As all of these tests demonstrate, the bifunctor laws hold for rose trees. The tests only showcase five examples, but I hope it gives you an intuition how any rose tree is a bifunctor. After all, the SelectNode, SelectLeaf, and SelectBoth methods are all generic, and they behave the same for all generic type arguments.

Summary #

Rose trees are bifunctors. You can translate the node and leaf dimension of a rose tree independently of each other, and the bifunctor laws hold for any pure translation, no matter how you compose the projections.

As always, there can be performance differences between the various compositions, but the outputs will be the same regardless of composition.

A functor, and by extension, a bifunctor, is a structure-preserving map. This means that any projection preserves the structure of the underlying container. For rose trees this means that the shape of the tree remains the same. The number of leaves remain the same, as does the number of internal nodes.

Next: Contravariant functors.

The catamorphism for a tree with different types of nodes and leaves is made up from two functions.

This article is part of an article series about catamorphisms. A catamorphism is a universal abstraction that describes how to digest a data structure into a potentially more compact value.

This article presents the catamorphism for a rose tree, as well as how to identify it. The beginning of this article presents the catamorphism in C#, with examples. The rest of the article describes how to deduce the catamorphism. This part of the article presents my work in Haskell. Readers not comfortable with Haskell can just read the first part, and consider the rest of the article as an optional appendix.

A rose tree is a general-purpose data structure where each node in a tree has an associated value. Each node can have an arbitrary number of branches, including none. The distinguishing feature from a rose tree and just any tree is that internal nodes can hold values of a different type than leaf values.

The diagram shows an example of a tree of internal integers and leaf strings. All internal nodes contain integer values, and all leaves contain strings. Each node can have an arbitrary number of branches.

C# catamorphism #

As a C# representation of a rose tree, I'll use the Church-encoded rose tree I've previously described. The catamorphism is this extension method:

public static TResult Cata<N, L, TResult>(
    this IRoseTree<N, L> tree,
    Func<N, IEnumerable<TResult>, TResult> node,
    Func<L, TResult> leaf)
{
    return tree.Match(
        node: (n, branches) => node(n, branches.Select(t => t.Cata(node, leaf))),
        leaf: leaf);
}

Like most of the other catamorphisms shown in this article series, this one consists of two functions. One that handles the leaf case, and one that handles the partially reduced node case. Compare it with the tree catamorphism: notice that the rose tree catamorphism's node function is identical to the the tree catamorphism. The leaf function, however, is new.

In previous articles, you've seen other examples of catamorphisms for Church-encoded types. The most common pattern has been that the Church encoding (the Match method) was also the catamorphism, with the Peano catamorphism being the only exception so far. When it comes to the Peano catamorphism, however, I'm not entirely confident that the difference between Church encoding and catamorphism is real, or whether it's just an artefact of the way I originally designed the Church encoding.

When it comes to the present rose tree, however, notice that the catamorphisms is distinctly different from the Church encoding. That's the reason I called the method Cata instead of Match.

The method simply delegates the leaf handler to Match, while it adds behaviour to the node case. It works the same way as for the 'normal' tree catamorphism.

Examples #

You can use Cata to implement most other behaviour you'd like IRoseTree<N, L> to have. In a future article, you'll see how to turn the rose tree into a bifunctor and functor, so here, we'll look at some other, more ad hoc, examples. As is also the case for the 'normal' tree, you can calculate the sum of all nodes, if you can associate a number with each node.

Consider the example tree in the above diagram. You can create it as an IRoseTree<int, string> object like this:

IRoseTree<int, string> exampleTree =
    RoseTree.Node(42,
        RoseTree.Node(1337,
            new RoseLeaf<int, string>("foo"),
            new RoseLeaf<int, string>("bar")),
        RoseTree.Node(2112,
            RoseTree.Node(90125,
                new RoseLeaf<int, string>("baz"),
                new RoseLeaf<int, string>("qux"),
                new RoseLeaf<int, string>("quux")),
            new RoseLeaf<int, string>("quuz")),
        new RoseLeaf<int, string>("corge"));

If you want to calculate a sum for a tree like that, you can use the integers for the internal nodes, and perhaps the length of the strings of the leaves. That hardly makes much sense, but is technically possible:

> exampleTree.Cata((x, xs) => x + xs.Sum(), x => x.Length)
93641

Perhaps slightly more useful is to count the number of leaves:

> exampleTree.Cata((_, xs) => xs.Sum(), _ => 1)
7

A leaf node has, by definition, exactly one leaf node, so the leaf lambda expression always returns 1. In the node case, xs contains the partially summed leaf node count, so just Sum those together while ignoring the value of the internal node.

You can also measure the maximum depth of the tree:

> exampleTree.Cata((_, xs) => 1 + xs.Max(), _ => 0)
3

Consistent with the example for 'normal' trees, you can arbitrarily decide that the depth of a leaf node is 0, so again, the leaf lambda expression just returns a constant value. The node lambda expression takes the Max of the partially reduced xs and adds 1, since an internal node represents another level of depth in a tree.

Rose tree F-Algebra #

As in the previous article, I'll use Fix and cata as explained in Bartosz Milewski's excellent article on F-Algebras.

As always, start with the underlying endofunctor:

data RoseTreeF a b c =
    NodeF { nodeValue :: a, nodes :: ListFix c }
  | LeafF { leafValue :: b }
  deriving (Show, Eq, Read)
 
instance Functor (RoseTreeF a b) where
  fmap f (NodeF x ns) = NodeF x $ fmap f ns
  fmap _    (LeafF x) = LeafF x

Instead of using Haskell's standard list ([]) for the nodes, I've used ListFix from the article on list catamorphism. This should, hopefully, demonstrate how you can build on already established definitions derived from first principles.

As usual, I've called the 'data' types a and b, and the carrier type c (for carrier). The Functor instance as usual translates the carrier type; the fmap function has the type (c -> c1) -> RoseTreeF a b c -> RoseTreeF a b c1.

As was the case when deducing the recent catamorphisms, Haskell isn't too happy about defining instances for a type like Fix (RoseTreeF a b). To address that problem, you can introduce a newtype wrapper:

newtype RoseTreeFix a b =
  RoseTreeFix { unRoseTreeFix :: Fix (RoseTreeF a b) } deriving (Show, Eq, Read)

You can define Bifunctor, Bifoldable, Bitraversable, etc. instances for this type without resorting to any funky GHC extensions. Keep in mind that ultimately, the purpose of all this code is just to figure out what the catamorphism looks like. This code isn't intended for actual use.

A pair of helper functions make it easier to define RoseTreeFix values:

roseLeafF :: b -> RoseTreeFix a b
roseLeafF = RoseTreeFix . Fix . LeafF
 
roseNodeF :: a -> ListFix (RoseTreeFix a b) -> RoseTreeFix a b
roseNodeF x = RoseTreeFix . Fix . NodeF x . fmap unRoseTreeFix

roseLeafF creates a leaf node:

Prelude Fix List RoseTree> roseLeafF "ploeh"
RoseTreeFix {unRoseTreeFix = Fix (LeafF "ploeh")}

roseNodeF is a helper function to create internal nodes:

Prelude Fix List RoseTree> roseNodeF 6 (consF (roseLeafF 0) nilF)
RoseTreeFix {unRoseTreeFix = Fix (NodeF 6 (ListFix (Fix (ConsF (Fix (LeafF 0)) (Fix NilF)))))}

Even with helper functions, construction of RoseTreeFix values is cumbersome, but keep in mind that the code shown here isn't meant to be used in practice. The goal is only to deduce catamorphisms from more basic universal abstractions, and you now have all you need to do that.

Haskell catamorphism #

At this point, you have two out of three elements of an F-Algebra. You have an endofunctor (RoseTreeF a b), and an object c, but you still need to find a morphism RoseTreeF a b c -> c. Notice that the algebra you have to find is the function that reduces the functor to its carrier type c, not any of the 'data types' a or b. This takes some time to get used to, but that's how catamorphisms work. This doesn't mean, however, that you get to ignore a or b, as you'll see.

As in the previous articles, start by writing a function that will become the catamorphism, based on cata:

roseTreeF = cata alg . unRoseTreeFix
  where alg (NodeF x ns) = undefined
        alg    (LeafF x) = undefined

While this compiles, with its undefined implementations, it obviously doesn't do anything useful. I find, however, that it helps me think. How can you return a value of the type c from the LeafF case? You could pass a function argument to the roseTreeF function and use it with x:

roseTreeF fl = cata alg . unRoseTreeFix
  where alg (NodeF x ns) = undefined
        alg    (LeafF x) = fl x

While you could, technically, pass an argument of the type c to roseTreeF and then return that value from the LeafF case, that would mean that you would ignore the x value. This would be incorrect, so instead, make the argument a function and call it with x. Likewise, you can deal with the NodeF case in the same way:

roseTreeF :: (a -> ListFix c -> c) -> (b -> c) -> RoseTreeFix a b -> c
roseTreeF fn fl = cata alg . unRoseTreeFix
  where alg (NodeF x ns) = fn x ns
        alg    (LeafF x) = fl x

This works. Since cata has the type Functor f => (f a -> a) -> Fix f -> a, that means that alg has the type f a -> a. In the case of RoseTreeF, the compiler infers that the alg function has the type RoseTreeF a b c -> c, which is just what you need!

You can now see what the carrier type c is for. It's the type that the algebra extracts, and thus the type that the catamorphism returns.

This, then, is the catamorphism for a rose tree. As has been the most common pattern so far, it's a pair, made from two functions. It's still not the only possible catamorphism, since you could trivially flip the arguments to roseTreeF, or the arguments to fn.

I've chosen the representation shown here because it's similar to the catamorphism I've shown for a 'normal' tree, just with the added function for leaves.

Basis #

You can implement most other useful functionality with roseTreeF. Here's the Bifunctor instance:

instance Bifunctor RoseTreeFix where
  bimap f s = roseTreeF (roseNodeF . f) (roseLeafF . s)

Notice how naturally the catamorphism implements bimap.

From that instance, the Functor instance trivially follows:

instance Functor (RoseTreeFix a) where
  fmap = second

You could probably also add Applicative and Monad instances, but I find those hard to grasp, so I'm going to skip them in favour of Bifoldable:

instance Bifoldable RoseTreeFix where
  bifoldMap f = roseTreeF (\x xs -> f x <> fold xs)

The Bifoldable instance enables you to trivially implement the Foldable instance:

instance Foldable (RoseTreeFix a) where
  foldMap = bifoldMap mempty

You may find the presence of mempty puzzling, since bifoldMap takes two functions as arguments. Is mempty a function?

Yes, mempty can be a function. Here, it is. There's a Monoid instance for any function a -> m, where m is a Monoid instance, and mempty is the identity for that monoid. That's the instance in use here.

Just as RoseTreeFix is Bifoldable, it's also Bitraversable:

instance Bitraversable RoseTreeFix where
  bitraverse f s =
    roseTreeF (\x xs -> roseNodeF <$> f x <*> sequenceA xs) (fmap roseLeafF . s)

You can comfortably implement the Traversable instance based on the Bitraversable instance:

instance Traversable (RoseTreeFix a) where
  sequenceA = bisequenceA . first pure

That rose trees are Traversable turns out to be useful, as a future article will show.

Relationships #

As was the case for 'normal' trees, the catamorphism for rose trees is more powerful than the fold. There are operations that you can express with the Foldable instance, but other operations that you can't. Consider the tree shown in the diagram at the beginning of the article. This is also the tree that the above C# examples use. In Haskell, using RoseTreeFix, you can define that tree like this:

exampleTree =
  roseNodeF 42 (
    consF (
      roseNodeF 1337 (
        consF (roseLeafF "foo") $
        consF (roseLeafF "bar") nilF)) $
    consF (
      roseNodeF 2112 (
        consF (
          roseNodeF 90125 (
            consF (roseLeafF "baz") $
            consF (roseLeafF "qux") $
            consF (roseLeafF "quux") nilF)) $
        consF (roseLeafF "quuz") nilF)) $
    consF (
      roseLeafF "corge")
    nilF)

You can trivially calculate the sum of string lengths of all leaves, using only the Foldable instance:

Prelude RoseTree> sum $ length <$> exampleTree
25

You can also fairly easily calculate a sum of all nodes, using the length of the strings as in the above C# example, but that requires the Bifoldable instance:

Prelude Data.Bifoldable Data.Semigroup RoseTree> bifoldMap Sum (Sum . length) exampleTree
Sum {getSum = 93641}

Fortunately, we get the same result as above.

Counting leaves, or measuring the depth of a tree, on the other hand, is impossible with the Foldable instance, but interestingly, it turns out that counting leaves is possible with the Bifoldable instance:

countLeaves :: (Bifoldable p, Num n) => p a b -> n
countLeaves = getSum . bifoldMap (const $ Sum 0) (const $ Sum 1)

This works well with the example tree:

Prelude RoseTree> countLeaves exampleTree
7

Notice, however, that countLeaves works for any Bifoldable instance. Does that mean that you can 'count the leaves' of a tuple? Yes, it does:

Prelude RoseTree> countLeaves ("foo", "bar")
1
Prelude RoseTree> countLeaves (1, 42)
1

Or what about EitherFix:

Prelude RoseTree Either> countLeaves $ leftF "foo"
0
Prelude RoseTree Either> countLeaves $ rightF "bar"
1

Notice that 'counting the leaves' of tuples always returns 1, while 'counting the leaves' of Either always returns 0 for Left values, and 1 for Right values. This is because countLeaves considers the left, or first, data type to represent internal nodes, and the right, or second, data type to indicate leaves.

You can further follow that train of thought to realise that you can convert both tuples and EitherFix values to small rose trees:

fromTuple :: (a, b) -> RoseTreeFix a b
fromTuple (x, y) = roseNodeF x (consF (roseLeafF y) nilF)
 
fromEitherFix :: EitherFix a b -> RoseTreeFix a b
fromEitherFix = eitherF (`roseNodeF` nilF) roseLeafF

The fromTuple function creates a small rose tree with one internal node and one leaf. The label of the internal node is the first value of the tuple, and the label of the leaf is the second value. Here's an example:

Prelude RoseTree> fromTuple ("foo", 42)
RoseTreeFix {unRoseTreeFix = Fix (NodeF "foo" (ListFix (Fix (ConsF (Fix (LeafF 42)) (Fix NilF)))))}

The fromEitherFix function turns a left value into an internal node with no leaves, and a right value into a leaf. Here are some examples:

Prelude RoseTree Either> fromEitherFix $ leftF "foo"
RoseTreeFix {unRoseTreeFix = Fix (NodeF "foo" (ListFix (Fix NilF)))}
Prelude RoseTree Either> fromEitherFix $ rightF 42
RoseTreeFix {unRoseTreeFix = Fix (LeafF 42)}

While counting leaves can be implemented using Bifoldable, that's not the case for measuring the depths of trees (I think; leave a comment if you know of a way to do this with one of the instances shown here). You can, however, measure tree depth with the catamorphism:

treeDepth :: RoseTreeFix a b -> Integer
treeDepth = roseTreeF (\_ xs -> 1 + maximum xs) (const 0)

The implementation is similar to the implementation for 'normal' trees. I've arbitrarily decided that leaves have a depth of zero, so the function that handles leaves always returns 0. The function that handles internal nodes receives xs as a partially reduced list of depths below the node in question. Take the maximum of those and add 1, since each internal node has a depth of one.

Prelude RoseTree> treeDepth exampleTree
3

This, hopefully, illustrates that the catamorphism is more capable, and that the fold is just a (list-biased) specialisation.

Summary #

The catamorphism for rose trees is a pair of functions. One function transforms internal nodes with their partially reduced branches, while the other function transforms leaves.

For a realistic example of using a rose tree in a real program, see Picture archivist in Haskell.

This article series has so far covered progressively more complex data structures. The first examples (Boolean catamorphism and Peano catamorphism) were neither functors, applicatives, nor monads. All subsequent examples, on the other hand, are all of these, and more. The next example presents a functor that's neither applicative nor monad, yet still foldable. Obviously, what functionality it offers is still based on a catamorphism.

Next: Full binary tree catamorphism.

Comments

A rose tree is a tree with leaf nodes of one type, and internal nodes of another.

This article is part of a series of articles about Church encoding. In the previous articles, you've seen how to implement a Maybe container, and how to implement an Either container. Through these examples, you've learned how to model sum types without explicit language support. In this article, you'll see how to model a rose tree.

A rose tree is a general-purpose data structure where each node in a tree has an associated value. Each node can have an arbitrary number of branches, including none. The distinguishing feature from a rose tree and just any tree is that internal nodes can hold values of a different type than leaf values.

The diagram shows an example of a tree of internal integers and leaf strings. All internal nodes contain integer values, and all leaves contain strings. Each node can have an arbitrary number of branches.

Contract #

In C#, you can represent the fundamental structure of a rose tree with a Church encoding, starting with an interface:

public interface IRoseTree<N, L>
{
    TResult Match<TResult>(
        Func<N, IEnumerable<IRoseTree<N, L>>, TResult> node,
        Func<L, TResult> leaf);
}

The structure of a rose tree includes two mutually exclusive cases: internal nodes and leaf nodes. Since there's two cases, the Match method takes two arguments, one for each case.

The interface is generic, with two type arguments: N (for Node) and L (for leaf). Any consumer of an IRoseTree<N, L> object must supply two functions when calling the Match method: a function that turns a node into a TResult value, and a function that turns a leaf into a TResult value.

Both cases must have a corresponding implementation.

Leaves #

The leaf implementation is the simplest:

public sealed class RoseLeaf<N, L> : IRoseTree<N, L>
{
    private readonly L value;
 
    public RoseLeaf(L value)
    {
        this.value = value;
    }
 
    public TResult Match<TResult>(
        Func<N, IEnumerable<IRoseTree<N, L>>, TResult> node,
        Func<L, TResult> leaf)
    {
        return leaf(value);
    }
 
    public override bool Equals(object obj)
    {
        if (!(obj is RoseLeaf<N, L> other))
            return false;
 
        return Equals(value, other.value);
    }
 
    public override int GetHashCode()
    {
        return value.GetHashCode();
    }
}

The RoseLeaf class is an Adapter over a value of the generic type L. As is always the case with Church encoding, it implements the Match method by unconditionally calling one of the arguments, in this case the leaf function, with its adapted value.

While it doesn't have to do this, it also overrides Equals and GetHashCode. This is an immutable class, so it's a great candidate to be a Value Object. Making it a Value Object makes it easier to compare expected and actual values in unit tests, among other benefits.

Nodes #

The node implementation is slightly more complex:

public sealed class RoseNode<N, L> : IRoseTree<N, L>
{
    private readonly N value;
    private readonly IEnumerable<IRoseTree<N, L>> branches;
 
    public RoseNode(N value, IEnumerable<IRoseTree<N, L>> branches)
    {
        this.value = value;
        this.branches = branches;
    }
 
    public TResult Match<TResult>(
        Func<N, IEnumerable<IRoseTree<N, L>>, TResult> node,
        Func<L, TResult> leaf)
    {
        return node(value, branches);
    }
 
    public override bool Equals(object obj)
    {
        if (!(obj is RoseNode<N, L> other))
            return false;
 
        return Equals(value, other.value)
            && Enumerable.SequenceEqual(branches, other.branches);
    }
 
    public override int GetHashCode()
    {
        return value.GetHashCode() ^ branches.GetHashCode();
    }
}

A node contains both a value (of the type N) and a collection of sub-trees, or branches. The class implements the Match method by unconditionally calling the node function argument with its constituent values.

Again, it overrides Equals and GetHashCode for the same reasons as RoseLeaf. This isn't required to implement Church encoding, but makes comparison and unit testing easier.

Usage #

You can use the RoseLeaf and RoseNode constructors to create new trees, but it sometimes helps to have a static helper method to create values. It turns out that there's little value in a helper method for leaves, but for nodes, it's marginally useful:

public static IRoseTree<N, L> Node<N, L>(N value, params IRoseTree<N, L>[] branches)
{
    return new RoseNode<N, L>(value, branches);
}

This enables you to create tree objects, like this:

IRoseTree<string, int> tree =
    RoseTree.Node("foo", new RoseLeaf<string, int>(42), new RoseLeaf<string, int>(1337));

That's a single node with the label "foo" and two leaves with the values 42 and 1337, respectively. You can create the tree shown in the above diagram like this:

IRoseTree<int, string> exampleTree =
    RoseTree.Node(42,
        RoseTree.Node(1337,
            new RoseLeaf<int, string>("foo"),
            new RoseLeaf<int, string>("bar")),
        RoseTree.Node(2112,
            RoseTree.Node(90125,
                new RoseLeaf<int, string>("baz"),
                new RoseLeaf<int, string>("qux"),
                new RoseLeaf<int, string>("quux")),
            new RoseLeaf<int, string>("quuz")),
        new RoseLeaf<int, string>("corge"));

You can add various extension methods to implement useful functionality. In later articles, you'll see some more compelling examples, so here, I'm only going to show a few basic examples. One of the simplest features you can add is a method that will tell you if an IRoseTree<N, L> object is a node or a leaf:

public static IChurchBoolean IsLeaf<N, L>(this IRoseTree<N, L> source)
{
    return source.Match<IChurchBoolean>(
        node: (_, __) => new ChurchFalse(),
        leaf: _ => new ChurchTrue());
}
 
public static IChurchBoolean IsNode<N, L>(this IRoseTree<N, L> source)
{
    return new ChurchNot(source.IsLeaf());
}

Since this article is part of the overall article series on Church encoding, and the purpose of that article series is also to show how basic language features can be created from Church encodings, these two methods return Church-encoded Boolean values instead of the built-in bool type. I'm sure you can imagine how you could change the type to bool if you'd like.

You can use these methods like this:

> IRoseTree<Guid, double> tree = new RoseLeaf<Guid, double>(-3.2);
> tree.IsLeaf()
ChurchTrue { }
> tree.IsNode()
ChurchNot(ChurchTrue)
> IRoseTree<long, string> tree = RoseTree.Node<long, string>(42);
> tree.IsLeaf()
ChurchFalse { }
> tree.IsNode()
ChurchNot(ChurchFalse)

In a future article, you'll see some more compelling examples.

Terminology #

It's not entirely clear what to call a tree like the one shown here. The Wikipedia entry doesn't state one way or the other whether internal node types ought to be distinguishable from leaf node types, but there are indications that this could be the case. At least, it seems that the term isn't well-defined, so I took the liberty to retcon the name rose tree to the data structure shown here.

In the paper that introduces the rose tree term, Meertens writes:

"We consider trees whose internal nodes may fork into an arbitrary (natural) number of sub-trees. (If such a node has zero descendants, we still consider it internal.) Each external node carries a data item. No further information is stored in the tree; in particular, internal nodes are unlabelled."

public class Unit
{
    public readonly static Unit Instance = new Unit();
 
    private Unit() { }
}

This enables you to create a rose tree according to Meertens' definition:

IRoseTree<Unit, int> meertensTree =
    RoseTree.Node(Unit.Instance,
        RoseTree.Node(Unit.Instance,
            RoseTree.Node(Unit.Instance,
                new RoseLeaf<Unit, int>(2112)),
            new RoseLeaf<Unit, int>(42),
            new RoseLeaf<Unit, int>(1337),
            new RoseLeaf<Unit, int>(90125)),
        RoseTree.Node(Unit.Instance,
            new RoseLeaf<Unit, int>(1984)),
        new RoseLeaf<Unit, int>(666));

Visually, you could draw it like this:

Thus, the tree structure shown here seems to be a generalisation of Meertens' original definition.

I'm not a mathematician, so I may have misunderstood some things. If you have a better name than rose tree for the data structure shown here, please leave a comment.

Yeats #

Now that we're on the topic of rose tree as a term, you may, as a bonus, enjoy a similarly-titled poem:

THE ROSE TREE

"O words are lightly spoken"
Said Pearse to Connolly,
"Maybe a breath of politic words
Has withered our Rose Tree;
Or maybe but a wind that blows
Across the bitter sea."

"It needs to be but watered,"
James Connolly replied,
"To make the green come out again
And spread on every side,
And shake the blossom from the bud
To be the garden's pride."

"But where can we draw water"
Said Pearse to Connolly,
"When all the wells are parched away?
O plain as plain can be
There's nothing but our own red blood
Can make a right Rose Tree."

Summary #

You may occasionally find use for a tree that distinguishes between internal and leaf nodes. You can model such a tree with a Church encoding, as shown in this article.

Next: Catamorphisms.

Comments

type HeterogeneousRoseTree = Tree

type LeafLabeledRoseTree b = Tree () b

type BranchLabeledRoseTree a = Tree a ()

type HomogeneousRoseTree a = Tree a a

type UnlabelledRoseTree = Tree () ()